Graph the quadratic y = 4x ^ 2 + 3x - 8 What is the vertex of this quadratic? (- 0.375, - 8.563); (1.088, 0); (- 1.838, 0); (0, - 8)
To find the vertex of a quadratic equation in the form y = ax^2 + bx + c, use the formula:
x = -b / 2a
In this case, a = 4 and b = 3, so:
x = -3 / (2 * 4) = -3/8 = -0.375
To find the value of y at the vertex, substitute the value of x into the equation:
y = 4(-0.375)^2 + 3(-0.375) - 8
y = 4(0.140625) - 1.125 - 8
y = 0.5625 - 1.125 - 8
y = -8.5625
Therefore, the vertex of the quadratic is (-0.375, -8.5625).