Is the point (1,-8) a valid solution to y<=4x-2
Show work
To check if the point (1,-8) is a valid solution to the inequality y <= 4x-2, we substitute the values x = 1 and y = -8 into the inequality and see if the inequality holds true.
Substituting the values:
-8 ≤ 4(1) - 2
Simplifying:
-8 ≤ 4 - 2
-8 ≤ 2
Since -8 is less than or equal to 2, the inequality holds true. Therefore, the point (1,-8) is a valid solution to y ≤ 4x-2.