What would be the final velocity if a 800g cart initially traveling 5.6 m/s collided with a 400g cart 2?
To find the final velocity after the collision of two carts, we can use the principle of conservation of momentum.
According to the principle of conservation of momentum, the total momentum before the collision is equal to the total momentum after the collision, assuming no external forces act on the system.
The momentum of an object is given by the product of its mass and velocity: momentum = mass × velocity
Initially, the momentum of the 800g cart is: momentum1 = (mass1) × (velocity1) = (0.8 kg) × (5.6 m/s) = 4.48 kg·m/s
The momentum of the 400g cart is: momentum2 = (mass2) × (velocity2)
After the collision, the final momentum is the sum of the individual momenta of the two carts: momentum_final = momentum1 + momentum2
Substituting the values, we have: momentum_final = 4.48 kg·m/s + (0.4 kg) × (velocity2)
Since the total momentum is conserved, momentum_final = momentum_initial = 4.48 kg·m/s.
Now, we can solve for velocity2:
4.48 kg·m/s = 4.48 kg·m/s + (0.4 kg) × (velocity2)
Subtracting 4.48 kg·m/s from both sides:
0 kg·m/s = 0.4 kg × (velocity2)
Dividing both sides by 0.4 kg:
0 = velocity2
Therefore, the final velocity of the 400g cart (cart 2) after the collision is 0 m/s.