Question 23
Tito and Michael put 1200 joules of work into pushing a box up a ramp, but only 300 joules of work is output for moving the box. What is the efficiency of the ramp?
Efficiency = Output work/Input work x 100%
a. .25 %
b. 360,000 %
c. 25 %
d. 4 %
To calculate the efficiency of the ramp, we use the formula:
Efficiency = (Output work / Input work) x 100%
Given that Tito and Michael put 1200 joules of work into pushing the box up the ramp, and only 300 joules of work is output, we can substitute these values into the formula:
Efficiency = (300 joules / 1200 joules) x 100%
Simplifying this expression:
Efficiency = 0.25 x 100%
Efficiency = 25%
Therefore, the efficiency of the ramp is 25%.
Answer: c. 25%