A common trait found in orange tabby cats is the following: being awesome (A) is dominant to being average (a).
A male cat that is homozygous dominant for the A trait is mated with a female cat that is homozygous recessive.
For a cross with four offspring, what is the probability that they will have an offspring who is heterozygous?
___ OUT OF ___
To determine the probability of having an offspring who is heterozygous, we can use a Punnett square.
First, let's assign the alleles for the male cat as AA (homozygous dominant) and for the female cat as aa (homozygous recessive).
Male (AA) x Female (aa)
A A
a a
When we cross the two parents, each parent can pass on one allele to their offspring. The male will always pass on the dominant A allele, while the female will always pass on the recessive a allele. Therefore, all the offspring will be heterozygous (Aa).
So, the probability of having an offspring who is heterozygous is 4 out of 4 or 100%.