How many grams of a 1203 are produced from 0.85 mol of a 10. H three
To determine the number of grams produced, we need to use the molar mass of the substance.
The molar mass of H3 is 3.0 g/mol (since there are 3 hydrogen atoms in one molecule).
Now, let's calculate the molar mass of 1203.
The molar mass of 1203 can be broken down into individual elements:
- The molar mass of O is 16.0 g/mol (since there is 1 oxygen atom in one molecule).
- The molar mass of 120 is 20.0 g/mol (since there are 3 hydrogen atoms in one molecule).
Adding the molar masses of O and H, we get:
1203 = 1(16.0 g/mol) + 2(1.0 g/mol) + 3(20.0 g/mol)
1203 = 16.0 g/mol + 2.0 g/mol + 60.0 g/mol
1203 = 78.0 g/mol
Now that we know the molar mass of 1203 is 78.0 g/mol, we can calculate the number of grams produced:
Number of grams = Number of moles × Molar mass
Number of grams = 0.85 mol × 78.0 g/mol
Number of grams = 66.3 g
Therefore, 66.3 grams of 1203 are produced from 0.85 mol of H3.