A volume of a gas at 111 kPa was measured at 0.326 L what will be the volume if the pressure is adjusted to 192 kg pascals
To solve this problem, we can use Boyle's Law, which states that the volume of a gas is inversely proportional to the pressure. Mathematically, we can express this relationship as:
P1 * V1 = P2 * V2
Where P1 is the initial pressure, V1 is the initial volume, P2 is the final pressure, and V2 is the final volume.
Let's substitute the given values into the equation:
(111 kPa) * (0.326 L) = (192 kPa) * V2
Now, let's isolate V2 to solve for the final volume:
V2 = (111 kPa * 0.326 L) / (192 kPa)
V2 = 35.986 kPa L / 192 kPa
V2 ≈ 0.187 L
Therefore, the volume of the gas will be approximately 0.187 liters when the pressure is adjusted to 192 kPa.