A 25kg chair initially at rest on a horizontal floor requires a 165N horizontal force to set it in motion once the chair is in a 127n horizontal force keeps it moving a a constant velocity
Find the coefficient of static friction between the chair and floor
To find the coefficient of static friction between the chair and the floor, we need to use the equation:
static friction = coefficient of static friction * normal force
where the normal force is equal to the weight of the chair.
The weight of the chair can be calculated using the formula:
weight = mass * gravity
where the mass of the chair is 25 kg and the acceleration due to gravity is approximately 9.8 m/s^2. Therefore:
weight = 25 kg * 9.8 m/s^2
weight = 245 N
Now, we can use the given information to calculate the force required to set the chair in motion, and the force required to keep it moving at a constant velocity.
The force required to set the chair in motion is 165 N, and the force required to keep it moving at a constant velocity is 127 N.
The force required to set the chair in motion is equal to the sum of the force of static friction and the applied force:
165 N = static friction + 127 N
To find the coefficient of static friction, we rearrange the equation to solve for the frictional force:
static friction = 165 N - 127 N
static friction = 38 N
Now we can substitute the known values into the equation for static friction:
38 N = coefficient of static friction * 245 N
Solving for the coefficient of static friction:
coefficient of static friction = 38 N / 245 N
coefficient of static friction ā 0.155
Therefore, the coefficient of static friction between the chair and the floor is approximately 0.155.