Suppose an investment of $3,800 doubles in value every decade. The function f(x)=3800times2^x gives the value of the investment after x decades. How much is the investment worth after 2 decades?
a
$76,000
b
$15,200
c
$152,000
d
$15,000
To find the value of the investment after 2 decades, we substitute x=2 into the function f(x)=3800*2^x:
f(2) = 3800*2^2 = 3800*4 = 15200
Therefore, the investment is worth $15,200 after 2 decades.
The correct option is b) $15,200.