At a temperature of 280 K, the gas in a cylinder has a volume of 20.0 liters.
If the volume of the gas is decreased to 10.0 liters, what must the temperature be for the gas to remain at a constant pressure?
140 K
273 K
560 K
5600 K
To keep the gas at a constant pressure, we can use the formula:
(V1 / T1) = (V2 / T2)
Where V1 and V2 are the initial and final volumes, and T1 and T2 are the initial and final temperatures.
Given:
V1 = 20.0 L
T1 = 280 K
V2 = 10.0 L
T2 = ?
Plugging in the values:
(20.0 / 280) = (10.0 / T2)
Cross-multiplying:
20.0T2 = 2800
Solving for T2:
T2 = 2800 / 20.0
T2 = 140
Therefore, the temperature must be 140 K for the gas to remain at a constant pressure.