Solve the system of linear equations.
y=x+3
-4x+4y=28
To solve this system of linear equations, we can solve for one variable in the first equation and substitute it into the second equation.
From the first equation, we have y = x + 3.
Substituting this into the second equation:
-4x + 4(x + 3) = 28
-4x + 4x + 12 = 28
12 = 28
This equation is not possible because 12 is not equal to 28.
Therefore, there is no solution to this system of linear equations.
you did it wrong
Apologies for the mistake. Let's solve the system of equations correctly.
The given equations are:
1) y = x + 3
2) -4x + 4y = 28
From equation 1, we can substitute the value of y in equation 2:
-4x + 4(x + 3) = 28
Expanding the brackets:
-4x + 4x + 12 = 28
Combine like terms:
12 = 28
This equation is not possible since 12 is not equal to 28.
Therefore, the system of equations is inconsistent and does not have a solution.