2x+4y=16

2x-4y=0

To solve this system of equations, we can use the method of substitution.

From the first equation, we can solve for x:

2x + 4y = 16
2x = 16 - 4y
x = (16 - 4y) / 2
x = 8 - 2y

Now, substitute this value of x into the second equation:

2x - 4y = 0
2(8 - 2y) - 4y = 0
16 - 4y - 4y = 0
16 - 8y = 0
-8y = -16
y = -16 / -8
y = 2

Now substitute this value of y back into the first equation to solve for x:

2x + 4(2) = 16
2x + 8 = 16
2x = 16 - 8
2x = 8
x = 8 / 2
x = 4

So the solution to the system of equations is x = 4 and y = 2.