Our middle school is having a fall carnival. Admission into the carnival is $3 and each game inside the carnival costs $.25. Write an inequality that represents the possible number of games that can be played having $10. What is the maximum number of games that can be played?(1 point)
Responses
0.25x+3≤10
; 28 games
0 point 2 5 x plus 3 is less than or equal to 10; 28 games
0.25x−3≤10
; 52 games
0 point 2 5 x minus 3 is less than or equal to 10; 52 games
0.25x−3<10
; 52 games
0.25x−3<10
; 52 games
0.25x+3<10
; 28 games
0.25x+3<10
; 28 games
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The correct inequality is: 0.25x + 3 ≤ 10
To find the maximum number of games that can be played, we need to solve this inequality for x:
0.25x + 3 ≤ 10
Subtract 3 from both sides:
0.25x ≤ 7
Now divide both sides by 0.25 (or multiply both sides by 4):
x ≤ 28
Therefore, the maximum number of games that can be played is 28.