Vehicle 2 Mass = 1,500 kg Velocity = 20 m/s Calculate the amount of force that would act on Vehicle 2 if it crashes into a wall and it takes half a second for Vehicle 2 to come to a stop upon collision. a. Step 1: Calculate the acceleration of the vehicle as its velocity changes from 20 to 0 m/s in 0.01 seconds. b. Step 2: Apply Newton’s Second Law of Motion to determine the force exerted by the vehicle on the wall during the crash. c. Step 3: Apply Newton’s Third Law of Motion to determine the force exerted by the wall on the vehicle.

a. To calculate the acceleration of the vehicle, we can use the formula:

acceleration = (final velocity - initial velocity) / time

Given:
Initial velocity (u) = 20 m/s
Final velocity (v) = 0 m/s
Time (t) = 0.01 seconds

acceleration = (0 - 20) / 0.01
acceleration = -2000 m/s^2 (negative sign indicates deceleration)

b. According to Newton's Second Law of Motion, the force (F) exerted on an object is given by:

force = mass * acceleration

Given:
Mass (m) = 1500 kg
Acceleration (a) = -2000 m/s^2

force = 1500 * (-2000)
force = -3,000,000 N (negative sign indicates force in the opposite direction of motion)

c. According to Newton's Third Law of Motion, the force exerted by the wall on the vehicle will be equal in magnitude but opposite in direction to the force exerted by the vehicle on the wall. Therefore, the force exerted by the wall on the vehicle would also be -3,000,000 N.