Set up the square for each of the crosses listed below:
A woman that is a carrier for colorblindness
marries a male that is not colorblind.
What is the percent chance of having a female that is colorblind?
What is the percent chance of having a male that is colorblind?
What is the percent chance of having any child that is colorblind?
To set up the Punnett square, we need to represent the genotype of each parent.
Assuming "C" represents the dominant allele for normal color vision and "c" represents the recessive allele for colorblindness, the genotype of the woman (carrier) can be represented as "Cc" and the genotype of the non-colorblind male as "CC".
Using the Punnett square, we can determine the possible genotypes and their corresponding probabilities for the offspring:
| C | C
----|----|----
c | Cc | Cc
----|----|----
c | Cc | Cc
There are four possible combinations in the square, with each having an equal probability of 25% (1/4).
Now let's determine the percentage of having a female that is colorblind. To do this, we need to consider the possible genotypes that result in a female being colorblind.
In the Punnett square, the genotype "cc" represents colorblindness. In this case, there are two combinations that result in a female being colorblind: Cc and Cc.
Therefore, the percentage chance of having a female that is colorblind is 2 out of 4, which is 50%.
Next, let's determine the percentage chance of having a male that is colorblind. Again, we need to consider the possible genotypes that result in a male being colorblind.
As colorblindness is a recessive trait, a male can only be colorblind if he inherits the recessive allele "c" from his mother. In this case, there are two combinations in the Punnett square where the male would be colorblind: Cc and Cc.
Therefore, the percentage chance of having a male that is colorblind is also 2 out of 4, which is 50%.
Finally, let's determine the percentage chance of having any child that is colorblind. To calculate this, we consider all the possible combinations in the Punnett square that result in colorblindness, regardless of gender.
In this case, there are four combinations that result in colorblindness: Cc, Cc, Cc, and Cc.
Therefore, the percentage chance of having any child that is colorblind is 4 out of 4, which is 100%.
1. What is the percent chance of having a female that is colorblind?
2. What is the percent chance of having a male that is colorblind?
3. What is the percent chance of having any child that is colorblind?
1. The percent chance of having a female that is colorblind is 50%.
2. The percent chance of having a male that is colorblind is also 50%.
3. The percent chance of having any child that is colorblind is 100%.