Given that △ABC is a right triangle with ∠A=90°, ∠B=25°, and BC=5 inches, which of the following correctly uses the sine ratio to find the length of AC¯¯¯¯¯¯¯¯? (1 point)
AC=5/sin25°
AC=5sin65°
AC=5sin25°
AC=5/sin65°
The correct answer is AC=5/sin25°.
In a right triangle, the sine ratio is defined as the length of the side opposite the angle divided by the length of the hypotenuse. In this case, AC is the side opposite the angle A, and BC is the hypotenuse. The sine of angle A can be found using the formula sin(A) = opposite/hypotenuse.
Since BC = 5 inches is the length of the hypotenuse and AC is the length of the side opposite angle A, we have AC/sin(A) = BC.
Substituting the given values, we get AC/sin(25°) = 5.
Rearranging the equation to solve for AC, we get AC = 5/sin(25°).