Part A Estimate 1012−38 using benchmark values. Your equation must show the estimate for each fraction and the final estimate for the expression. (2 points) Uhh, like, you know, let's find a common thingy for 12 and 8. Hmm, oh yeah, the smallest number both can go into is 24! So, let's change the numbers to make 'em have the same bottom part, like this: 10/12 - 3/8 = (10 times 2)/(12 times 2) - (3 times 3)/(8 times 3) = 20/24 - 9/24 And now, we can subtract the fraction-y parts: 20/24 - 9/24 = (20 minus 9)/24 = 11/24 So, ta-da, the answer is 11/24! Question 2 Part B Solve 1012−38 . Show your solution as an equation. (2 points) let's find a common bottom thingy for 12 and 8. Like, we can see that 12 can times ouchie by 2 to get 24, and 8 can get multiplied by 3 to get 24 too. So, we change the numbers to make 'em have the same bottom part, like this: 10/12 - 3/8 = (10 times 2)/(12 times 2) - (3 times 3)/(8 times 3) = 20/24 - 9/24 Now, we just subtract the fractions: 20/24 - 9/24 = (20 minus 9)/24 = 11/24 So the answer is 11/24 Question 3 Part C Calculate the difference between your estimate in Part A and the actual value you calculated in Part B. Be sure to show this solution as an equation. Based on this difference, do you think your estimate for Part A was reasonable? Explain. (2 points)
The difference between the estimate in Part A (11/24) and the actual value in Part B (11/24) is 0/24.
Since 0/24 is equal to 0, the estimate in Part A was reasonable because it is exactly equal to the actual value calculated in Part B.