Given point A 2,4 on the triangle quadrant 1 where is the new point if the triangle is rotated 270 degrees counterclockwise
To rotate a point counterclockwise by 270 degrees, we need to find the new coordinates by applying the following rotation matrices:
x' = x * cos(θ) - y * sin(θ)
y' = x * sin(θ) + y * cos(θ)
where θ is the angle of rotation (270 degrees).
Let's calculate the new coordinates:
x' = 2 * cos(270) - 4 * sin(270)
y' = 2 * sin(270) + 4 * cos(270)
Using trigonometric identities:
x' = 2 * 0 - 4 * (-1)
y' = 2 * (-1) + 4 * 0
Simplifying:
x' = 0 + 4
y' = -2 + 0
Therefore, the new point after rotating point A (2,4) counterclockwise by 270 degrees is (4,-2).