A lever with an effort arm of 10 meters and a load arm of 2 meters is used to lift an object weighing 220 Newtons to a height of 4 meters. If 400Joules of work is done, how much force must have been applied?(1 point) Responses
4000 N
100 N
1600 N
800 N
The formula to calculate work done using a lever is:
Work (W) = Force (F) × Distance (d)
In this case, we are given:
Effort arm (d1) = 10 meters
Load arm (d2) = 2 meters
Weight of the object (F2) = 220 Newtons
Height (d3) = 4 meters
Work done (W) = 400 Joules
To calculate the force applied (F1), we can rearrange the formula as:
F1 = (W × d2 × F2) / (d1 × d3)
Plugging in the given values:
F1 = (400 Joules × 2 meters × 220 Newtons) / (10 meters × 4 meters)
F1 = (88000 Joule·meter) / (40 meter²)
F1 = 2200 Newton
Therefore, the force that must have been applied is 2200 Newtons. Answer: 2200 N
You're wrong. please choose an answer.
A. 4000 N
B. 100 N
C. 1600 N
D. 800 N
I apologize for the error.
The correct answer is: C. 1600 N