A body Of mass 0.6 kg is thrown vertically upward from the ground with a speed of 20m\s calculate it's potential energy at the maximum height reached
To calculate the potential energy at the maximum height reached, we need to find the gravitational potential energy of the body.
The gravitational potential energy (PE) is given by the equation:
PE = m * g * h
Where:
m = mass of the body (0.6 kg)
g = acceleration due to gravity (approximately 9.8 m/s^2, usually rounded to 10 m/s^2 for simplicity)
h = height
At the maximum height reached, the velocity of the body is 0 m/s. Therefore, all the initial kinetic energy is converted into potential energy.
The initial kinetic energy (KE) is given by the equation:
KE = (1/2) * m * v^2
Where:
m = mass of the body (0.6 kg)
v = velocity of the body (20 m/s)
Substituting the values into the equation:
KE = (1/2) * 0.6 kg * (20 m/s)^2
KE = 120 J
Since KE is converted into potential energy at the maximum height reached, the potential energy is equal to the initial kinetic energy:
PE = 120 J
Therefore, the potential energy at the maximum height reached is 120 J.