i think i have to simplify.... but the question just says:
(2y-3)^2
possible answers:
a.4y^2+9
b.4y^2-6y+9
c.4y^2-12y+9
d.4y^2+12y+9
separate and multiply based on
FOIL
first
outer
inner
last
(2y-3)^2=
(2y-3)(2y-3) then use foil and multiply the first term, outer term, inner terms then last terms .
(2y-3)(2y-3)
first terms multiplied
2y*2y= 4y^2
outer terms multiplied
2y*(-3)=-6y
inner terms multiplied
(-2y)*3=-6y
last terms multiplied
(-3)*(-3)=9
Now combined FOIL (first outer inner and last terms )
4y^2-6y-6y+9= but now you can combine the -6y's so (-6y-6y=-12y)
and you get 4y^2-12y+9
duplicate post
inner terms multiplied
2y*(-3)=-6y
it is the same as the outer terms multiplied (the negative was misplaced before)
Oh..it was a duplicate?
Oh well I solved it Dr.Bob.=D
anyways..ha
thank you...
Your welcome =)
To simplify the expression (2y-3)^2, we need to expand and simplify it. In this case, we have a binomial raised to the power of 2, which means we need to multiply the binomial by itself.
To do that, we use the formula (a+b)^2 = a^2 + 2ab + b^2, where a is the first term and b is the second term of the binomial.
In our case, a = 2y and b = -3. Now let's substitute these values into the formula:
(2y-3)^2 = (2y)^2 + 2(2y)(-3) + (-3)^2
Next, let's simplify each term:
(2y)^2 = 4y^2
2(2y)(-3) = -12y
(-3)^2 = 9
Now combine these simplified terms:
(2y-3)^2 = 4y^2 - 12y + 9
Therefore, the correct answer is option c. 4y^2 - 12y + 9.