What equation has a graph perpendicular to the graph of 5x = 20y - 12?
A. y = -4x + 2
B. y = -1/4x - 5/3
C.y = 4x+1
D. y = 1/4× + 3/5
To find the equation that is perpendicular to the graph of 5x = 20y - 12, we can determine the slope of the given equation by rearranging it into slope-intercept form (y = mx + b), where m is the slope.
Starting with 5x = 20y - 12:
20y = 5x + 12
y = (5/20)x + 12/20
y = (1/4)x + 3/5
The slope of the given equation is 1/4. The slope of a line perpendicular to this line will have a negative reciprocal slope, which is -4.
Therefore, the equation that has a graph perpendicular to the graph of 5x = 20y - 12 is y = -4x + 2.
The correct answer is A. y = -4x + 2.