The PH of 0.012M solution of weak base BOH wasdetermined to be 11.40 what is the Kb value of the base?
To find the Kb value of the weak base, we first need to find the pOH of the solution.
pOH = 14 - pH
= 14 - 11.40
= 2.6
Next, we can convert the pOH value to OH- concentration using the formula:
OH- = 10^(-pOH)
= 10^(-2.6)
= 2.51 x 10^(-3) M
Since we know that the concentration of the weak base, BOH, is 0.012 M, we can use the formula for Kb:
Kb = [OH-]^2 / [BOH]
= (2.51 x 10^(-3))^2 / 0.012
= 6.32 x 10^(-7)
Therefore, the Kb value of the base is 6.32 x 10^(-7).