Hank raises mealworms. In a square of compost 5 ft by 5 ft, he can have 2,000 mealworms. How many mealworms can he have if his square of compost has a side length that is six times longer?
(1 point)
• 12,000
• 60,000
• 72.000
• 300.000
If the side length of the compost square is 5 ft, and he can have 2,000 mealworms, then the area of the square is 5 ft x 5 ft = 25 sq ft.
If the new side length of the compost square is six times longer, then the new side length would be 5 ft x 6 = 30 ft.
The new area of the square is 30 ft x 30 ft = 900 sq ft.
If Hank can have 2,000 mealworms in 25 sq ft, then he can have 900 sq ft x 2,000 mealworms = 1,800,000 mealworms.
Therefore, the correct option is 300,000 mealworms.