The students in Mr. McIntyre's class and the students in Mrs. Ramos's class were asked how many pets they each have. The dot plots below show the results.
Mr. McIntyre's Class
0 has 5, 1 has 5, 2 has 4, 3 has 1, 4 has 0, 5 has 0
Mrs. Ramos's Class
0 has 1, 1 has 2, 2 has 2, 3 has 4, 4 has 3, 5 has 3
Which statement correctly compares the means of the data in the dot plots?
A. The mean for Mr. McIntyre's class is about 2 more than the mean for Mrs. Ramos's class.
B. The mean for Mrs. Ramos's class is about 2 more than the mean for Mr. McIntyre's class.
C. The mean for Mr. Mcintyre's class is about 1 more than the mean for Mrs. Ramos's class.
D. The mean for Mrs. Ramos's class is about 1 more than the mean for Mr. McIntyre's class.
To find the mean of a set of data, we would add up all the values and then divide by the total number of values.
For Mr. McIntyre's class, the sum of the values is $0\cdot5+1\cdot5+2\cdot4+3\cdot1+4\cdot0+5\cdot0= 5 + 5\cdot2 + 3\cdot1 = 5 + 10 + 3 = 18$.
The total number of values is $5+5+4+1+0+0=15$.
Therefore, the mean for Mr. McIntyre's class is $18/15 = 1.2$.
For Mrs. Ramos's class, the sum of the values is $0\cdot1+1\cdot2+2\cdot2+3\cdot4+4\cdot3+5\cdot3= 0 + 2\cdot2 + 3\cdot4 + 4\cdot3 + 5\cdot3 = 0 + 4 + 12 + 12 + 15 = 43$.
The total number of values is $1+2+2+4+3+3=15$.
Therefore, the mean for Mrs. Ramos's class is $43/15 \approx 2.87$.
Comparing the means, the mean for Mrs. Ramos's class is about 1.67 more than the mean for Mr. McIntyre's class.
Therefore, the statement that correctly compares the means of the data in the dot plots is:
B. The mean for Mrs. Ramos's class is about 2 more than the mean for Mr. McIntyre's class.