Xavior took a total of 124 quarters and dimes to trade in for cash at the bank. He got exactly $25 back. How many quarters did he have? A. 40 B. 62 C. 84 D. 100
Let's represent the number of quarters Xavior had as q and the number of dimes as d. We can set up a system of equations to represent the given information.
q + d = 124 (equation 1)
0.25q + 0.10d = 25 (equation 2)
To solve this system, we can multiply equation 1 by 0.10 to get:
0.10q + 0.10d = 12.4 (equation 3)
Subtract equation 3 from equation 2:
0.25q + 0.10d - (0.10q + 0.10d) = 25 - 12.4
0.15q = 12.6
q = 12.6/0.15
q = 84
Therefore, Xavior had 84 quarters.
The correct answer is C. 84.