Question A science teacher has a supply of 50% sugar solution and a supply of 80% sugar solution. How much of each solution should the teacher mix together to get 105 mL of 60% sugar solution for an experiment ? (1 point) Responses 70 mL of the 50% solution and 35 mL of the 80% solution 70 mL of the 50% solution and 35 mL of the 80% solution 35 mL of the 50% solution and 70 mL of the 80% solution 35 mL of the 50% solution and 70 mL of the 80% solution 70 mL of the 50% solution and 70 mL of the 80% solution 70 mL of the 50% solution and 70 mL of the 80% solution 35 mL of the 50% solution and 35 mL of the 80% solutionl
To solve this problem, we can set up an equation based on the amount of sugar in each solution.
Let x represent the amount (in mL) of the 50% sugar solution, and let y represent the amount (in mL) of the 80% sugar solution.
We can set up the equation:
0.50x + 0.80y = 0.60(105)
Simplifying, we get:
0.50x + 0.80y = 63
To solve for x and y, we can use the method of substitution.
From the second equation, we can solve for x in terms of y:
x = 63 - 0.80y
Substituting this expression for x in the first equation, we get:
0.50(63 - 0.80y) + 0.80y = 63
Simplifying, we get:
31.5 - 0.40y + 0.80y = 63
Combine the y terms:
0.40y = 31.5
Now we can solve for y:
y = 31.5 / 0.40 = 78.75 mL
Substituting this value of y back into the expression for x, we get:
x = 63 - 0.80(78.75) = 63 - 63 = 0 mL
Therefore, the correct answer is:
35 mL of the 50% solution and 70 mL of the 80% solution