Solve the system of equations:
*Remember no spaces in your answer (#,#), type infinite or type none.
{5x+3y=15'
{x-6y=3
By eliminating x from the system of equations, we can solve for y.
We can do this by multiplying the second equation by 5, which gives us:
5(x - 6y) = 5(3)
5x - 30y = 15
Now we can subtract this equation from the first equation to eliminate x:
(5x + 3y) - (5x - 30y) = 15 - 15
33y = 0
Dividing both sides of the equation by 33, we get:
y = 0
Substituting this value back into either of the original equations, we find that:
5x + 3(0) = 15
5x = 15
x = 3
So the solution to the system of equations is x = 3, y = 0.
Therefore, the answer is (3, 0).