Tickets to the basketball game are $1.50 off the regular prices. Dea buys 6 tickets. If her total cost was $51, what is the total cost of the tickets. Write the answer in the form of p(x+q)=r
Let's represent the regular price of a ticket as x.
If the tickets are $1.50 off the regular price, then the discounted price per ticket is x - $1.50.
Since Dea buys 6 tickets, the total cost of the tickets is 6 * (x - $1.50).
We are given that the total cost of the tickets is $51.
So, 6 * (x - $1.50) = $51.
Distributing the 6, we get 6x - 9 = $51.
Adding 9 to both sides, we have 6x = $60.
Dividing both sides by 6, we obtain x = $10.
Therefore, the total cost of the tickets is 6 * (x - $1.50) = 6 * ($10 - $1.50) = 6 * $8.50 = $51.
So, the total cost of the tickets is p(x+q)=r, where p = 6, q = -$1.50, and r = $51. Answer: 6(x - $1.50) = $51.