A 65kg diver stands still on a tower 10.0m above water.
To solve this problem, we need to find the potential energy of the diver standing on the tower.
The potential energy (PE) is given by the equation: PE = mgh
Where:
m = mass of the diver = 65kg
g = acceleration due to gravity = 9.8 m/s²
h = height of the tower = 10.0m
By substituting the values into the equation, we get:
PE = 65kg × 9.8 m/s² × 10.0m
PE = 6,370 J
Therefore, the potential energy of the diver standing on the tower is 6,370 Joules.