What is the probability that an AaBbCC man and an aabbCc woman can have an AaBbCc
Offspring?
The probability of an AaBbCC man and an aabbCc woman having an AaBbCc offspring is 1/4 or 25%.
To determine this, we need to understand the inheritance pattern of the three traits. Assume the letter "A" represents the dominant allele for Trait 1, "a" represents the recessive allele for Trait 1, "B" represents the dominant allele for Trait 2, "b" represents the recessive allele for Trait 2, "C" represents the dominant allele for Trait 3, and "c" represents the recessive allele for Trait 3.
The AaBbCC man will contribute one of each allele for Trait 1, Trait 2, and Trait 3 to the offspring. The aabbCc woman will contribute the recessive allele for Trait 1, the recessive allele for Trait 2, and one of each allele for Trait 3.
When these alleles combine, there are four possible combinations for each trait in the offspring:
1. AB (dominant allele for Trait 1 and dominant allele for Trait 2)
2. Ab (dominant allele for Trait 1 and recessive allele for Trait 2)
3. aB (recessive allele for Trait 1 and dominant allele for Trait 2)
4. ab (recessive allele for Trait 1 and recessive allele for Trait 2)
Therefore, the probability of the offspring having the AaBbCc genotype is 1/4 or 25%.