Calculate the percentage by mass of nitrogen in calcium trioxonitrate(v). (ca=40, N=14, O=16
To calculate the percentage by mass of nitrogen in calcium trioxonitrate(V), we need to consider the molar mass of each element in the compound.
The molar mass of calcium (Ca) is 40 g/mol, nitrogen (N) is 14 g/mol, and oxygen (O) is 16 g/mol.
The molecular formula for calcium trioxonitrate(V) is Ca(NO3)2. This means that one mole of calcium trioxonitrate(V) contains one mole of calcium (Ca), two moles of nitrogen (N), and six moles of oxygen (O).
Now, let's calculate the molar mass of calcium trioxonitrate(V):
Molar mass of Ca(NO3)2 = (1 x molar mass of Ca) + (2 x molar mass of N) + (6 x molar mass of O)
= (1 x 40 g/mol) + (2 x 14 g/mol) + (6 x 16 g/mol)
= 40 g/mol + 28 g/mol + 96 g/mol
= 164 g/mol
To find the percentage by mass of nitrogen, we need to calculate the mass of nitrogen in one mole of calcium trioxonitrate(V) and divide it by the molar mass of the compound:
Mass of nitrogen (N) in one mole of Ca(NO3)2 = (2 x molar mass of N)
= (2 x 14 g/mol)
= 28 g/mol
Percentage by mass of nitrogen = (Mass of nitrogen / Molar mass of Ca(NO3)2) x 100%
= (28 g/mol / 164 g/mol) x 100%
= 0.17 x 100%
≈ 17%
Therefore, the percentage by mass of nitrogen in calcium trioxonitrate(V) is approximately 17%.