An experiment to determine osmosis was conducted. Russet potato cubes were placed in a solution of sucrose at a concentration of 0.308 M. The experiment was carried out at approximately 24° C. Calculate the solute potential of solution B. Solve.
To calculate the solute potential of solution B, we need to convert the concentration of sucrose into solute potential using the equation:
Ψ = -iCRT
Where:
Ψ = solute potential
i = ionization constant (for sucrose, it is 1 because it does not ionize)
C = molar concentration in mol/L
R = pressure constant (0.0831 L bar mol^-1 K^-1)
T = temperature in Kelvin
First, we need to convert the temperature from Celsius to Kelvin:
T(K) = T(C) + 273.15
T(K) = 24 + 273.15 = 297.15 K
Thus, the temperature in Kelvin is 297.15 K.
Next, we can substitute the values into the equation:
Ψ = -1 * (0.308 mol/L) * (0.0831 L bar mol^-1 K^-1) * (297.15 K)
Calculating further:
Ψ = -1 * (0.308) * (0.0831) * (297.15)
Ψ ≈ -7.79 bars
Therefore, the solute potential of solution B is approximately -7.79 bars.