What is the value of n so that the expression x^2+11x+n is a perfect square trinomial?
To determine the value of n, we need to find two numbers that when multiplied together, give the square term coefficient (x^2 coefficient) and when added together, give the linear term coefficient (x coefficient).
In this case, the square term coefficient is 1 and the linear term coefficient is 11.
To find two numbers that multiply to give 1 and add to give 11, we can deduce that the two numbers are 1 and 10.
Therefore, the value of n is (1 * 10) = 10.
So, the expression x^2 + 11x + 10 is a perfect square trinomial.