Calculate the difference (subtract) in electronegativities for each set of elements below.
Column A
1.
Nitrogen (N) and Fluorine (F) in NF3.
2.
Fluorine (F) and Fluorine (F) in F2.
1. The electronegativity of nitrogen (N) is 3.04 and the electronegativity of fluorine (F) is 3.98. Therefore, the difference in electronegativities between nitrogen and fluorine in NF3 is 3.98 - 3.04 = 0.94.
2. The electronegativity of fluorine (F) is 3.98. When comparing the electronegativity of an element to itself, the difference is always zero. Therefore, the difference in electronegativities between fluorine and itself in F2 is 0.