Which point is located on the line represented by the equation
y - 5 = 2/3 (x + 9)?
The equation of the given line is written in slope-intercept form, which is y = mx + b, where m represents the slope and b represents the y-intercept.
Comparing the given equation to the slope-intercept form, we find that the slope, m, is 2/3, and the y-intercept, b, is 5.
So, any point on the line will have a y-coordinate that is 5 units above or below another point and an x-coordinate that is 3 units to the right or left of that point.
One point located on the line can be found by substituting an arbitrary value for x into the equation and then solving for y.
Let's take x = 0:
y - 5 = 2/3 (0 + 9)
y - 5 = 2/3 * 9
y - 5 = 6
Simplifying:
y = 6 + 5
y = 11
So, the point (0, 11) is located on the line represented by the equation y - 5 = 2/3 (x + 9).