Find the surface area of a rectangular pyramid with these measurements: l= 15m, w= 12m, and h= 10m. Express your answer, as a decimal rounded to the nearest hundredth.
The surface area of a rectangular pyramid can be found by summing the areas of all its faces.
In this case, the pyramid has a rectangular base with dimensions of length 15 m and width 12 m. The area of the base is l*w = 15m * 12m = 180 m^2.
The pyramid also has four triangular faces. Each of these triangular faces has a base of 15 m and a height of 10 m (the height of the pyramid). The area of each triangular face is (1/2) * b * h = (1/2) * 15m * 10m = 75 m^2. Since there are four triangular faces, the total area of the triangular faces is 4 * 75 m^2 = 300 m^2.
To find the surface area, we sum the areas of the base and the triangular faces: 180 m^2 + 300 m^2 = 480 m^2.
Therefore, the surface area of the rectangular pyramid is 480 m^2.