Maya and her children went into a bakery where they sell cupcakes for $3 each and donuts for $1.75 each. Maya has $40 to spend and must buy at least 15 cupcakes and donuts altogether. If Maya decided to buy 11 donuts, determine the maximum number of cupcakes that she could buy
Maya has $40 to spend, and each cupcake costs $3, so she can buy a maximum of $40/$3 = <<40/3=13.33>>13.33 cupcakes.
Maya must buy at least 15 cupcakes and donuts altogether, and she decided to buy 11 donuts, so she must buy 15-11 = <<15-11=4>>4 cupcakes.
The maximum number of cupcakes Maya can buy is 4 because 13.33 < 4. Answer: \boxed{4}.
wrong bit
Apologies for the mistake. Let's correct it.
Maya has $40 to spend and the cost of each cupcake is $3. If she buys x cupcakes, the amount spent on cupcakes is 3x.
Maya must buy at least 15 cupcakes and donuts altogether. If she buys 11 donuts, she needs to buy a minimum of 15 - 11 = 4 cupcakes.
Since Maya has $40 to spend, the maximum amount she can spend on cupcakes is $40 - $1.75 × 11 (the amount spent on donuts), which is $40 - $19.25 = $20.75.
The maximum number of cupcakes Maya can buy is $20.75 ÷ $3 = 6.917. However, since she must buy a whole number of cupcakes, the maximum number of cupcakes she can buy is 6.
Therefore, Maya can buy a maximum of 6 cupcakes.