find the slope and the y-intercept
f(x) = -4x-9
The slope is
the y-intercept is (0, and ?)
All staight line equations are in the form
y=mx+c where m is the gradient and c is the intercept (0,c).
So compare your function with the general equation for a straight line and by inspection you can find m and c.
I get (0,-13)
How did you get that? Say the equation is y=-4x+9
In the form
y=mx+c it is
y=(-4)x+(-9)
so what is m and what is c?
To find the slope and y-intercept of the equation f(x) = -4x-9, we can compare it to the standard form of a linear equation, y = mx + b, where m represents the slope and b represents the y-intercept.
In the given equation, f(x) = -4x-9, we can see that the coefficient of x is -4, which is equivalent to the slope (m) of the equation.
Therefore, the slope of the equation f(x) = -4x-9 is -4.
To find the y-intercept, we need to determine the value of y when x is equal to 0.
Substituting x = 0 into the equation f(x) = -4x-9:
f(0) = -4(0) - 9
f(0) = 0 - 9
f(0) = -9
So, when x = 0, y = -9.
Therefore, the y-intercept is (0, -9).