What is the equation of a line with a slope of 3 and a point (3, 1) on the line?
Express the equation in the form of y=mx+b where m is the slope and b is the y-intercept.
The equation of a line can be expressed in the form y = mx + b, where m is the slope and b is the y-intercept.
Given that the slope is 3 and the point (3, 1) lies on the line, we can use the point-slope form of a linear equation to find the equation of the line.
The point-slope form is:
y - y1 = m(x - x1)
Substituting the given values:
y - 1 = 3(x - 3)
Expanding and simplifying:
y - 1 = 3x - 9
Rearranging to the form y = mx + b:
y = 3x - 9 + 1
y = 3x - 8
Therefore, the equation of the line with a slope of 3 and containing the point (3, 1) is y = 3x - 8.