Sue is wrapping books to give as gifts Book A has a length of 6.5 inches, a width of 1 inch, and a height of 8.5 inches. Book B has a length of 5.5 inches, a width of 2 inches, and a height of 8 inchesBased on surface area, which book will require less wrapping paper? (1 point)
To calculate the surface area, we need to find the sum of the areas of all the faces of each book.
For Book A:
- The area of the front and back faces is 6.5 inches * 8.5 inches = 55.25 square inches
- The area of the two side faces is 1 inch * 8.5 inches + 1 inch * 8.5 inches = 17 square inches
- The area of the top and bottom faces is 6.5 inches * 1 inch + 6.5 inches * 1 inch = 13 square inches
The total surface area of Book A is 55.25 + 17 + 13 = 85.25 square inches.
For Book B:
- The area of the front and back faces is 5.5 inches * 8 inches = 44 square inches
- The area of the two side faces is 2 inches * 8 inches + 2 inches * 8 inches = 32 square inches
- The area of the top and bottom faces is 5.5 inches * 2 inches + 5.5 inches * 2 inches = 22 square inches
The total surface area of Book B is 44 + 32 + 22 = 98 square inches.
Therefore, Book A will require less wrapping paper.