Part A
Rewrite the following system of equations in slope intercept form.
The system of equation is:
−6x+y = 10
−36x+6y=48
A. −6x=10−y and −36x=48−6y
B. y=6x+10 and y=6x+8
C. y=6x+10 and y=36x+48
D. None of the above
To rewrite the system of equations in slope-intercept form, we need to solve each equation for y.
1) −6x + y = 10
To isolate y, we can add 6x to both sides:
y = 6x + 10
2) −36x + 6y = 48
To isolate y, we can divide both sides by 6:
6y = 36x + 48
Divide by 6:
y = 6x + 8
Therefore, the system of equations in slope-intercept form is:
y = 6x + 10
y = 6x + 8
The correct answer is B. y = 6x + 10 and y = 6x + 8.
Part B
(1 point)
From the above slope intercept forms of the system of equations, the system has
none of above
infinite solutions
one solution s
no solutions
From the above slope-intercept forms of the system of equations (y = 6x + 10 and y = 6x + 8), we can see that both equations have the same slope (m = 6) but different y-intercepts (b = 10 and b = 8).
This means that the equations represent parallel lines.
Since parallel lines do not intersect, the system of equations has no solutions.
Therefore, the correct answer is "no solutions."
What is the solution to the system graphed?
-5,0 0, -4 and 0,1 -2,0
State your answer as an ordered pair (x,y)
To find the solution to the system graphed, we need to determine the point where the lines intersect.
Looking at the given coordinates (-5,0), (0,-4), (0,1), and (-2,0), it is not clear which lines these points belong to. Please provide more information or clarify the problem.