54x plus, 27, y+27y equals= 8181
minus, 18, x−18x minus, 4, y−4y equals= 1818
To solve this system of equations, we will first simplify each equation:
Equation 1: 54x + 27 + y + 27y = 8181
Simplifying, we get: 55x + 28y = 8154
Equation 2: -18x - 18 + y - 4y = 1818
Simplifying, we get: -18x - 3y = 1836
Now, we have a system of two equations with two variables:
55x + 28y = 8154
-18x - 3y = 1836
We can solve this system using any method we prefer. Let's use substitution:
From Equation 2, we can express y in terms of x:
-18x - 3y = 1836
-3y = 18x - 1836
y = -6x + 612
Now we substitute this expression for y in Equation 1:
55x + 28(-6x + 612) = 8154
55x - 168x + 17136 = 8154
-113x = -8982
x = 79
Now we substitute this value of x back into Equation 2 to find y:
-18x - 3y = 1836
-18(79) - 3y = 1836
-1422 - 3y = 1836
-3y = 3258
y = -1086
So the solution to the system of equations is x = 79 and y = -1086.