Use the equation of motion to answer the question.
x=x0+v0t+12at2
An object has a starting position of x = 2 m, a starting velocity of 4.5 m/s, and no acceleration. Which option shows the final position of the object after 2 s?
To find the final position of the object after 2 seconds, we need to substitute the given values into the equation of motion:
x = x0 + v0t + (1/2)at^2
Given:
x0 = 2 m (starting position)
v0 = 4.5 m/s (starting velocity)
a = 0 m/s^2 (acceleration)
t = 2 s (time)
Substituting these values into the equation:
x = 2 + 4.5(2) + (1/2)(0)(2^2)
x = 2 + 9 + 0
x = 11
Therefore, the final position of the object after 2 seconds is 11 meters.