a blue and red billiard ball, each with a mass of 0.15 kg, collide directly. before the collosion the blue ball had a velocity of 4m/s tot he east while the red ball countinues in motion. what is the speed and direction of the red ball after the collision
To solve this problem, we can use the principle of conservation of momentum.
Before the collision, the momentum of the system is given by the sum of the momenta of the two balls. The momentum of an object is defined as the product of its mass and velocity.
The momentum of the blue ball before the collision is calculated as:
Momentum of blue ball = Mass of blue ball * Velocity of blue ball
= 0.15 kg * 4 m/s (to the east)
= 0.6 kg·m/s (to the east)
Since the red ball continues in motion after the collision, its momentum remains the same.
Therefore, the momentum of the red ball after the collision is also 0.6 kg·m/s.
To find the speed and direction of the red ball after the collision, we need to calculate its velocity. Velocity is defined as the momentum divided by the mass.
So, Velocity of red ball after the collision = Momentum of red ball / Mass of red ball
= 0.6 kg·m/s / 0.15 kg
= 4 m/s (to the east)
Therefore, the speed and direction of the red ball after the collision is 4 m/s to the east.