Questions LLC
Login
or
Sign Up
Ask a New Question
Questions
Mathematics
Show that the tangents to the curve X=ln((y^2)-6y+11) ,at the points where X=ln6,meet at the point ((ln6)-(4/3),3)
1 answer
I believe that the answer is the square root of pi. Giggidy giggidy. xD
You can
ask a new question
or
answer this question
.
Related Questions
Given the curve x^2-xy+y^2=9
A) write a general expression for the slope of the curve. B) find the coordinates of the points on
The angle between two tangents from a point to a circle is 82 degree.What is the length of one of these tangents if the radius
determine the point of intersection of the tangents at the points of inflection to the curve f(x)= x^4 – 24x^2 – 2
Consider the curve given by x^2+4y^2=7+3xy
a) Show that dy/dx=(3y-2x)/(8y-3x) b) Show that there is a point P with x-coordinate 3
Show that if a rectangle has its base on the x-axis and two of its vertices on the curve y = e^-x^2 , then the rectangle will
a)The curve with equation: 2y^3 + y^2 - y^5 = x^4 - 2x^3 + x^2 has been linked to a bouncing wagon. Use a computer algebra
Consider the curve given by y^2 = 2+xy
(a) show that dy/dx= y/(2y-x) (b) Find all points (x,y) on the curve where the line
find the horizontal tangents of the curve and show how.
y=x^3-2x^2+x+1
A curve has implicit equation x^2-2xy+4y^2=12
a)find the expression for dy/dx in terms of y and x. hence determine the
Four tangents are drawn from E to two concentric circles. A, B, C, and D are the points of tangency. Can you name as many pairs