In the diagram, if the area of the isosceles triangle AOB is 22.6 sq ft and the area of sector OACB is 30.4 sq ft, what is the area of the segment ACB?
First, we need to find the area of the entire circle.
The area of the sector OACB is 30.4 sq ft. Since the sector covers 1/4th of the entire circle (due to the right angle that the sector makes at point O), the area of the circle can be found by multiplying the area of the sector by 4.
Therefore, the area of the entire circle is 30.4 sq ft * 4 = 121.6 sq ft.
Next, we need to subtract the area of the triangle AOB from the area of the circle to find the area of the segment ACB.
The area of the segment ACB is equal to the area of the circle minus the area of the triangle AOB.
So, the area of the segment ACB is 121.6 sq ft - 22.6 sq ft = 99 sq ft.
Therefore, the area of the segment ACB is 99 sq ft. Answer: \boxed{99}.