In the diagram, if the area of the segment ACB is 88.35 sq ft and the area of sector OACB is 130.12 sq ft, what is the area of the isosceles triangle AOB?
Let r be the radius of the circle.
The area of the sector OACB is (130.12/360)πr^2 = 1.26052r^2
The area of triangle OAC is 1/2 * OA * OC = 1/2 * r * r = 0.5r^2
The area of segment ACB is 0.5r^2 - 88.35
1.26052r^2 = 0.5r^2 - 88.35
0.76052r^2 = -88.35
r^2 = -88.35 / 0.76052 = -116.2240437
Since the radius cannot be negative, there must be an error in the calculations or in the given values.