se the equation of motion to answer the question.%0D%0A%0D%0Ax=x0+v0t+12at2%0D%0A%0D%0A=%0D%0A%0D%0A0%0D%0A+%0D%0A%0D%0A0%0D%0A%0D%0A+%0D%0A1%0D%0A2%0D%0A%0D%0A%0D%0A2%0D%0A %0D%0AAn object has a starting position of x = 2 m, a starting velocity of 4.5 m/s, and no acceleration. Which option shows the final position of the object after 2 s? %0D%0A%0D%0A(1 point)%0D%0AResponses%0D%0A%0D%0A9 m%0D%0A9 m%0D%0A%0D%0A11 m %0D%0A11 m %0D%0A%0D%0A18 m %0D%0A18 m %0D%0A%0D%0A5.5 m
To find the final position of the object after 2 seconds, we can use the equation of motion:
x = x0 + v0t + (1/2)at^2
Given:
x0 = 2 m (starting position)
v0 = 4.5 m/s (starting velocity)
a = 0 (acceleration)
t = 2 s (time)
Plugging in the values:
x = 2 + (4.5)(2) + (1/2)(0)(2^2)
x = 2 + 9 + 0
x = 11
So, the final position of the object after 2 seconds is 11 meters.