2^-2*2^?=2^10
To solve this equation, we need to calculate the value of the missing exponent. We know that 2^-2 * 2^? = 2^10.
First, let's simplify the left side of the equation by multiplying the exponents:
2^(-2) * 2^? = 2^(-2 + ?)
Now, we can rewrite the right side of the equation as 2^10:
2^(-2 + ?) = 2^10
Since the bases (2) are the same, the exponents must be equal:
-2 + ? = 10
To isolate the missing exponent, we can add 2 to both sides of the equation:
-2 + ? + 2 = 10 + 2
Simplifying this equation:
? = 12
Therefore, the value of the missing exponent ? is 12.
Simplify 2^5⋅2 and write your answer in exponential form. (Example: 5^25 not 25).
To simplify 2^5 * 2, we can add the exponents when multiplying with the same base.
So, 2^5 * 2 is the same as 2^(5+1) which simplifies to 2^6.
Therefore, the answer in exponential form is 2^6.
write your answer in exponential form. (Example: 5^25 not 25)
y^19/y
The answer in exponential form is 1/y.
thats wrong
Apologies for the mistake.
To express the simplified expression, y^19/y, in exponential form, we can rewrite it as:
(1/y) * y^19
Since we have y in the numerator and denominator, the y terms cancel out, resulting in:
1 * y^19
Hence, the expression y^19/y in exponential form is simply y^19.
thats wrong again
I apologize for the confusion once again. Let's correct the answer.
The expression y^19/y can be simplified using the quotient rule of exponents, which states that when dividing two numbers with the same base, you subtract the exponents.
In this case, y^19 divided by y can be simplified as:
y^(19-1) = y^18
Therefore, the expression y^19/y simplified and written in exponential form is y^18.